| Need help on chemistry redox titration!!urgently!! |
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a999911
Probably not a bot. Junior Member.
Joined: 02 Jan 2007
Posts: 3
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 Posted: Tue Jan 02, 2007 4:07 pm Post subject: Need help on chemistry redox titration!!urgently!! |
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5Fe2+ 8H+ + MnO4 - = 5FE3+ + Mn2+ + 4H2O
the question is asking me determine the % of iron II and iron III in a mixture containing both, where i am given 200cm3 of a solution containing 1.3g of iron ions(Fe 2+ Fe 3+) using potassium magnanete
(here is where i get confuse) You may assume that each of the 2 ions of is present to at least 30% by mass (doesnt this contradict the question?)
also, i tried calculating it out via those normal calculas titration method but i cant go any further unless if i know the vol. of potassium maganate used to titrate the iron solution.
Can i just make it up what vol. is required to titrate the iron solution with the potassium maganate??
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adrian
Regular
Joined: 20 Apr 2006
Posts: 44
Location: Bucharest, Romania
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| Posted: Thu Jan 11, 2007 10:13 pm Post subject: |
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it is more than simple. You must titrate the Fe2+/Fe3+ mixture with KMnO4 in acidic solution.The mixture will use the permangamante during the oxydation of Fe2+ to Fe3+. When all Fe2+ dissapeared the solution turns violet (KMnO4 in excess), then stop the titration.
The amount of permanganate used is to find the amount of Fe2+. The rest was Fe3+ from the beginning.
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