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conman1987
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Joined: 08 Mar 2005
Posts: 1

PostPosted: Tue Mar 08, 2005 8:30 am    Post subject: physical chemistry numerical Reply with quote

I need help with this question:

Q: Calculate the current required to deposit all the silver from silver nitrate solution containing 8.5g of silver nitrate in 60 minutes.

Thank you,
-pH.
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charco
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Joined: 07 Mar 2005
Posts: 96

PostPosted: Tue Mar 08, 2005 8:54 am    Post subject: Reply with quote

calculate the number of moles of silver present

moles = mass of silver nitrate/RMM silver nitrate

moles = 8.5/170 = 0.005 moles

Each silver ion has a 1+ charge therefore 0.005 moles silver requires 0.005 moles of electrons

1 mole of electrons = 98,500 coulombs of charge

Therefore 0.005 moles = 4925 coulombs

Charge = current(amps) x time (seconds)

4925 = current x 60 x 60

Current = 4925/3600

Hence current required = 1.368 amps


Last edited by charco on Tue Mar 08, 2005 8:55 am; edited 1 time in total
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