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wade
Junior Member
Joined: 25 Apr 2007
Posts: 4
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 Posted: Wed Apr 25, 2007 6:28 pm Post subject: please help |
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| How many grams of air would be in an otherwise empty 2.00-liter beverage container at a pressure of 750 torr and temperature of 27 °C? Since air is about one-fifth oxygen and four-fifths nitrogen, we often treat it as a single gas with an average molar mass of 29 g/mol.
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Hix3r
Regular
Joined: 24 Apr 2007
Posts: 43
Location: Hungary
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| Posted: Wed Apr 25, 2007 9:22 pm Post subject: |
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Again we have to use this formula:
p*V = n*R*T
p in Pa... 750 torr = 99991.78 Pa
V in cubic metres = 0.002 m3
R is a constant = 8.3145 whatever
T is in Kelvin = 300.15 K
n = (99991.78*0.002)/(8.3145*300.15) = 0.08 mol
So we have 0.08 mol gas in the bottle, and we know the molar mass.
1 mol of the gas is 29 g.
So 0.08 mol of the gas is 29*0.08 mol = 2.32 g of air. Pretty light huh?
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