Hix3r
Regular
Joined: 24 Apr 2007
Posts: 43
Location: Hungary
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 Posted: Sun Feb 17, 2008 4:04 pm Post subject: |
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according to the equation you need equal parts from potassium-iodide and iodine to make it work:
KI(aq) + I2(s) -> KI3(aq)
KI3 dissolves in water into K+ and I3-, which are soluble ions. So for 1 mol/l iodine solution you need 1 mol or 166 g KI per litre(which is 1 dm^3).
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